Optimal. Leaf size=376 \[ \frac {2 (b c-a d) \cot (e+f x) E\left (\text {ArcSin}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (1+\sec (e+f x))}{a-b}}}{a b \sqrt {a+b} f}-\frac {2 (b c-a d) \cot (e+f x) F\left (\text {ArcSin}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (1+\sec (e+f x))}{a-b}}}{a b \sqrt {a+b} f}-\frac {2 \sqrt {a+b} c \cot (e+f x) \Pi \left (\frac {a+b}{a};\text {ArcSin}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (1+\sec (e+f x))}{a-b}}}{a^2 f}+\frac {2 b (b c-a d) \tan (e+f x)}{a \left (a^2-b^2\right ) f \sqrt {a+b \sec (e+f x)}} \]
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Rubi [A]
time = 0.30, antiderivative size = 376, normalized size of antiderivative = 1.00, number of steps
used = 6, number of rules used = 6, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.240, Rules used = {4008, 4143,
4006, 3869, 3917, 4089} \begin {gather*} -\frac {2 c \sqrt {a+b} \cot (e+f x) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (\sec (e+f x)+1)}{a-b}} \Pi \left (\frac {a+b}{a};\text {ArcSin}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right )}{a^2 f}+\frac {2 b (b c-a d) \tan (e+f x)}{a f \left (a^2-b^2\right ) \sqrt {a+b \sec (e+f x)}}-\frac {2 (b c-a d) \cot (e+f x) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (\sec (e+f x)+1)}{a-b}} F\left (\text {ArcSin}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right )}{a b f \sqrt {a+b}}+\frac {2 (b c-a d) \cot (e+f x) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (\sec (e+f x)+1)}{a-b}} E\left (\text {ArcSin}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right )}{a b f \sqrt {a+b}} \end {gather*}
Antiderivative was successfully verified.
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Rule 3869
Rule 3917
Rule 4006
Rule 4008
Rule 4089
Rule 4143
Rubi steps
\begin {align*} \int \frac {c+d \sec (e+f x)}{(a+b \sec (e+f x))^{3/2}} \, dx &=\frac {2 b (b c-a d) \tan (e+f x)}{a \left (a^2-b^2\right ) f \sqrt {a+b \sec (e+f x)}}-\frac {2 \int \frac {-\frac {1}{2} \left (a^2-b^2\right ) c+\frac {1}{2} a (b c-a d) \sec (e+f x)+\frac {1}{2} b (b c-a d) \sec ^2(e+f x)}{\sqrt {a+b \sec (e+f x)}} \, dx}{a \left (a^2-b^2\right )}\\ &=\frac {2 b (b c-a d) \tan (e+f x)}{a \left (a^2-b^2\right ) f \sqrt {a+b \sec (e+f x)}}-\frac {2 \int \frac {-\frac {1}{2} \left (a^2-b^2\right ) c+\left (\frac {1}{2} a (b c-a d)-\frac {1}{2} b (b c-a d)\right ) \sec (e+f x)}{\sqrt {a+b \sec (e+f x)}} \, dx}{a \left (a^2-b^2\right )}-\frac {(b (b c-a d)) \int \frac {\sec (e+f x) (1+\sec (e+f x))}{\sqrt {a+b \sec (e+f x)}} \, dx}{a \left (a^2-b^2\right )}\\ &=\frac {2 (b c-a d) \cot (e+f x) E\left (\sin ^{-1}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (1+\sec (e+f x))}{a-b}}}{a b \sqrt {a+b} f}+\frac {2 b (b c-a d) \tan (e+f x)}{a \left (a^2-b^2\right ) f \sqrt {a+b \sec (e+f x)}}+\frac {c \int \frac {1}{\sqrt {a+b \sec (e+f x)}} \, dx}{a}-\frac {(b c-a d) \int \frac {\sec (e+f x)}{\sqrt {a+b \sec (e+f x)}} \, dx}{a (a+b)}\\ &=\frac {2 (b c-a d) \cot (e+f x) E\left (\sin ^{-1}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (1+\sec (e+f x))}{a-b}}}{a b \sqrt {a+b} f}-\frac {2 (b c-a d) \cot (e+f x) F\left (\sin ^{-1}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (1+\sec (e+f x))}{a-b}}}{a b \sqrt {a+b} f}-\frac {2 \sqrt {a+b} c \cot (e+f x) \Pi \left (\frac {a+b}{a};\sin ^{-1}\left (\frac {\sqrt {a+b \sec (e+f x)}}{\sqrt {a+b}}\right )|\frac {a+b}{a-b}\right ) \sqrt {\frac {b (1-\sec (e+f x))}{a+b}} \sqrt {-\frac {b (1+\sec (e+f x))}{a-b}}}{a^2 f}+\frac {2 b (b c-a d) \tan (e+f x)}{a \left (a^2-b^2\right ) f \sqrt {a+b \sec (e+f x)}}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 14.39, size = 1491, normalized size = 3.97 \begin {gather*} \frac {(b+a \cos (e+f x))^2 \sec (e+f x) (c+d \sec (e+f x)) \left (\frac {2 (-b c+a d) \sin (e+f x)}{a \left (a^2-b^2\right )}-\frac {2 \left (-b^2 c \sin (e+f x)+a b d \sin (e+f x)\right )}{a \left (a^2-b^2\right ) (b+a \cos (e+f x))}\right )}{f (d+c \cos (e+f x)) (a+b \sec (e+f x))^{3/2}}+\frac {2 (b+a \cos (e+f x))^{3/2} \sqrt {\sec (e+f x)} (c+d \sec (e+f x)) \sqrt {\frac {a+b-a \tan ^2\left (\frac {1}{2} (e+f x)\right )+b \tan ^2\left (\frac {1}{2} (e+f x)\right )}{1+\tan ^2\left (\frac {1}{2} (e+f x)\right )}} \left (a b \sqrt {\frac {-a+b}{a+b}} c \tan \left (\frac {1}{2} (e+f x)\right )+b^2 \sqrt {\frac {-a+b}{a+b}} c \tan \left (\frac {1}{2} (e+f x)\right )-a^2 \sqrt {\frac {-a+b}{a+b}} d \tan \left (\frac {1}{2} (e+f x)\right )-a b \sqrt {\frac {-a+b}{a+b}} d \tan \left (\frac {1}{2} (e+f x)\right )-2 a b \sqrt {\frac {-a+b}{a+b}} c \tan ^3\left (\frac {1}{2} (e+f x)\right )+2 a^2 \sqrt {\frac {-a+b}{a+b}} d \tan ^3\left (\frac {1}{2} (e+f x)\right )+a b \sqrt {\frac {-a+b}{a+b}} c \tan ^5\left (\frac {1}{2} (e+f x)\right )-b^2 \sqrt {\frac {-a+b}{a+b}} c \tan ^5\left (\frac {1}{2} (e+f x)\right )-a^2 \sqrt {\frac {-a+b}{a+b}} d \tan ^5\left (\frac {1}{2} (e+f x)\right )+a b \sqrt {\frac {-a+b}{a+b}} d \tan ^5\left (\frac {1}{2} (e+f x)\right )-2 i a^2 c \Pi \left (-\frac {a+b}{a-b};i \sinh ^{-1}\left (\sqrt {\frac {-a+b}{a+b}} \tan \left (\frac {1}{2} (e+f x)\right )\right )|\frac {a+b}{a-b}\right ) \sqrt {1-\tan ^2\left (\frac {1}{2} (e+f x)\right )} \sqrt {\frac {a+b-a \tan ^2\left (\frac {1}{2} (e+f x)\right )+b \tan ^2\left (\frac {1}{2} (e+f x)\right )}{a+b}}+2 i b^2 c \Pi \left (-\frac {a+b}{a-b};i \sinh ^{-1}\left (\sqrt {\frac {-a+b}{a+b}} \tan \left (\frac {1}{2} (e+f x)\right )\right )|\frac {a+b}{a-b}\right ) \sqrt {1-\tan ^2\left (\frac {1}{2} (e+f x)\right )} \sqrt {\frac {a+b-a \tan ^2\left (\frac {1}{2} (e+f x)\right )+b \tan ^2\left (\frac {1}{2} (e+f x)\right )}{a+b}}-2 i a^2 c \Pi \left (-\frac {a+b}{a-b};i \sinh ^{-1}\left (\sqrt {\frac {-a+b}{a+b}} \tan \left (\frac {1}{2} (e+f x)\right )\right )|\frac {a+b}{a-b}\right ) \tan ^2\left (\frac {1}{2} (e+f x)\right ) \sqrt {1-\tan ^2\left (\frac {1}{2} (e+f x)\right )} \sqrt {\frac {a+b-a \tan ^2\left (\frac {1}{2} (e+f x)\right )+b \tan ^2\left (\frac {1}{2} (e+f x)\right )}{a+b}}+2 i b^2 c \Pi \left (-\frac {a+b}{a-b};i \sinh ^{-1}\left (\sqrt {\frac {-a+b}{a+b}} \tan \left (\frac {1}{2} (e+f x)\right )\right )|\frac {a+b}{a-b}\right ) \tan ^2\left (\frac {1}{2} (e+f x)\right ) \sqrt {1-\tan ^2\left (\frac {1}{2} (e+f x)\right )} \sqrt {\frac {a+b-a \tan ^2\left (\frac {1}{2} (e+f x)\right )+b \tan ^2\left (\frac {1}{2} (e+f x)\right )}{a+b}}+i (a-b) (-b c+a d) E\left (i \sinh ^{-1}\left (\sqrt {\frac {-a+b}{a+b}} \tan \left (\frac {1}{2} (e+f x)\right )\right )|\frac {a+b}{a-b}\right ) \sqrt {1-\tan ^2\left (\frac {1}{2} (e+f x)\right )} \left (1+\tan ^2\left (\frac {1}{2} (e+f x)\right )\right ) \sqrt {\frac {a+b-a \tan ^2\left (\frac {1}{2} (e+f x)\right )+b \tan ^2\left (\frac {1}{2} (e+f x)\right )}{a+b}}+i (a-b) (2 b c+a (c-d)) F\left (i \sinh ^{-1}\left (\sqrt {\frac {-a+b}{a+b}} \tan \left (\frac {1}{2} (e+f x)\right )\right )|\frac {a+b}{a-b}\right ) \sqrt {1-\tan ^2\left (\frac {1}{2} (e+f x)\right )} \left (1+\tan ^2\left (\frac {1}{2} (e+f x)\right )\right ) \sqrt {\frac {a+b-a \tan ^2\left (\frac {1}{2} (e+f x)\right )+b \tan ^2\left (\frac {1}{2} (e+f x)\right )}{a+b}}\right )}{a \sqrt {\frac {-a+b}{a+b}} \left (a^2-b^2\right ) f (d+c \cos (e+f x)) (a+b \sec (e+f x))^{3/2} \left (-1+\tan ^2\left (\frac {1}{2} (e+f x)\right )\right ) \sqrt {\frac {1+\tan ^2\left (\frac {1}{2} (e+f x)\right )}{1-\tan ^2\left (\frac {1}{2} (e+f x)\right )}} \left (a \left (-1+\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )-b \left (1+\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(2009\) vs.
\(2(347)=694\).
time = 3.34, size = 2010, normalized size = 5.35
method | result | size |
default | \(\text {Expression too large to display}\) | \(2010\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {c + d \sec {\left (e + f x \right )}}{\left (a + b \sec {\left (e + f x \right )}\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {c+\frac {d}{\cos \left (e+f\,x\right )}}{{\left (a+\frac {b}{\cos \left (e+f\,x\right )}\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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